constructing binary \n
jeff at ccvcorp.com
Thu Sep 30 04:16:40 CEST 2004
Steven Arnold wrote:
> Is there a more elegant way to construct \[a-z] in a string than
> something like:
> s = '\\n'
> result = eval( "'%s'" ) % s
> Another ugly method would be to build a dict with all the different
> special letters I want as keys, and their corresponding values as
> values. Or I could have a huge if/elif structure. I can't make ord
> work, because while ord( '\n' ) gives me a reasonable integer that I
> can interpolate with %c, I don't have '\n', I have '\\n'.
No, you actually *do* have '\n', the single byte that represents ASCII
Traceback (most recent call last):
File "<interactive input>", line 1, in ?
TypeError: ord() expected a character, but string of length 2 found
>>> for char in '\\n':
... print ord(char)
Note that '\n' is a single byte, while '\\n' is two bytes. In the first
case, '\n' is interpreted as the single LF byte. In the second case,
'\\' collapses into a single backslash, giving you a backslash byte and
a 'n' byte.
When you type a string literal containing a backslash, if that backslash
can combine with the following character to make a valid escape code, it
*will* do so unless you've explicitly turned off escaping (by, e.g.,
using raw strings). Of course, if the combination is *not* a valid
escape code, then the backslash and following character will be
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