built-in function- module name clash

[Alex Martelli]

Olivier Vierlinck <Olivier.Vierlinck at iba.be> wrote:

> Hi,
> 
> I've a python script using somecalls to the abs() built-in function.
> 
> Now, I have to import a module named 'abs' too...
> The consequence if that line code like
> 
>         if (abs(a-b) < epsilon:
>               ...
> does not work anymore, with this error msg:
> 
>       TypeError: 'module' object is not callable
> 
> Clearly, the interpreter tries first to consider 'abs' as a module name
rather than a built-in function name.

Nope, it just uses the latest binding you requested for name 'abs',
whatever kind of object that may refer to, there's just one (at a given
time in a given scope).

> Any idea on how to force it to call the abs() fct? Some kind of scoping or
specific syntax?
> (I could rename the abs module too but ...)

A name at a given time in a scope can refer to ONE thing -- so either
'abs' names a function or it names a module, not both, in that one scope
at one and the same time.

You can import under a false name, no need to rename your abs.py:

import abs as myabs

or you can get an alias for the builtin before you trample on it:

builtin_abs = abs
import abs

and perhaps restore it later if you're done naming your abs module --
and other ways yet.  But you just can't have barename 'abs' refer to two
different thing as the same name in the same scope.


Alex