args v. *args passed to: os.path.join()

Pierre Fortin pfortin at
Sat Sep 18 20:59:40 CEST 2004

On Sat, 18 Sep 2004 20:08:35 +0200 Heiko wrote:

> Now, when you call:
> os.path.join(["a","b"])
> the list ends up in the a parameter, and because the function doesn't
> have to do anything (there are no more arguments), the list is returned
> unchanged (although this should probably raise a TypeError, anyone?).
   ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^  =======

That was the whole point; the rest was pretty much my understanding too...
I can't think of any reason why os.path.join() should ever be presented
anything but strings...  on the other hand, maybe it could
check for lists/tuples and use those to return the expected "a/b"...

Then again, I just checked a number of functions in os and os.path;
os.path.join() seems to be the only one which fails to return a

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