all pairs of items in a list without indexing?

jepler at unpythonic.net jepler at unpythonic.net
Tue Sep 28 23:57:01 CEST 2004


I think that Steven wants to generate all pairs of items in a list,
not successive pairs.  So for the input
    [1, 2, 3]
he wants
    [[1, 2], [1, 3], [2, 3]]
or some ordering of it, anyway.

I think that I would write
    def all_pairs(seq):
        l = len(seq)
        for i in range(l):
            for j in range(i+1, l):
                yield seq[i], seq[j]
(essentially the OP's first suggestion, but with 'len(seq)' prematurely
optimized out) Something about taking a slice of seq for the inner loop
doesn't seem right to me.

Jeff
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