py2exe windows apps path question

vincent wehren vincent at visualtrans.de
Tue Aug 2 22:07:19 CEST 2005


"Gregory Piñero" <gregpinero at gmail.com> schrieb im Newsbeitrag 
news:mailman.2635.1123008925.10512.python-list at python.org...
> If you need something that works both on a frozen app as well as an
> (unfrozen) python
> script, you'd be better off using something like:
>
>> def getAppPrefix():
>>     """Return the location the app is running from
>>     """
>>     isFrozen = False
>>     try:
>>         isFrozen = sys.frozen
>>     except AttributeError:
>>         pass
>>     if isFrozen:
>>         appPrefix = os.path.split(sys.executable)[0]
>>     else:
>>         appPrefix = os.path.split(os.path.abspath(sys.argv[0]))[0]
>>     return appPrefix
>>
>
>Vincent,
>
>This sounds interesting.  A few questions for you:
>Why don't I see sys.frozen in interpreter?
>Does it only appear when it is frozen?

Yes. The sys.frozen attribute is added by py2exe.

>What do you mean by frozen, how does python know?

Python doesn't know - it is just told so ;)

>What does sys.executable do?

sys.executable gives you the path of the executing binary. Normally, this 
will be something like
"c:\\python24\\python.exe" - since the interpreter is the executing binary.
Once you have frozen your python application, it will return the path to 
your app.


--

Vincent

>
>Thanks,
>
>Greg 





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