Regular expression to match a #
sjmachin at lexicon.net
Thu Aug 11 16:48:42 EDT 2005
> In article <42fb45d7$1 at news.eftel.com>,
> John Machin <sjmachin at lexicon.net> wrote:
>>Search for r'^something' can never be better/faster than match for
>>r'something', and with a dopey implementation of search [which Python's
>>re is NOT] it could be much worse. So please don't tell newbies to
>>search for r'^something'.
> You're somehow getting mixed up in thinking that "^" is some kind of
> "not" operator -- it's the start of line anchor in this context.
I can't imagine where you got that idea from.
If I change "[which Python's re is NOT]" to "[Python's re's search() is
not dopey]", does that help you?
The point was made in a context where the OP appeared to be reading a
line at a time and parsing it, and re.compile(r'something').match()
would do the job; re.compile(r'^something').search() will do the job too
-- BECAUSE ^ means start of line anchor -- but somewhat redundantly, and
very inefficiently in the failing case with dopey implementations of
search() (which apply match() at offsets 0, 1, 2, .....).
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