file access dialog

Eric Brunel eric_brunel at
Fri Aug 26 12:27:35 CEST 2005

On Fri, 26 Aug 2005 07:52:06 GMT, Wouter van Ooijen ( <wouter at> wrote:

> I have a tool in Python to which I want to add a small GUI. The tools
> currently runs everywhere PySerial is supported. I need a file-access
> dialog. What is the preffered way to to this? Is there a
> platform-independent file-access dialog available, or should I use the
> windows native version when running on windows (and how do I do that)?

Tkinter has a file acces dialog available with the same API on all platforms. It is also mapped to the standard dialog on Windows. Since Tkinter is certainly installed by default with Python, if a file dialog is everything you need, you probably don't have to look further.

To use the dialog, just do:

 from Tkinter import Tk
 from tkFileDialog import askopenfilename
## Tk needs a main window to work, so create one and hide it
root = Tk()
## Ask the file name
fileName = askopenfilename(filetypes=[('Python files', '*.py'), ('All files', '*')])
if fileName:
   print 'open', fileName
   print 'cancelled'
## Over

python -c "print ''.join([chr(154 - ord(c)) for c in 'U(17zX(%,5.zmz5(17;8(%,5.Z65\'*9--56l7+-'])"

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