Strange email.Parser error?

[Anthony Botrel]

Hi,

in the call fp.read(8192) the function read() gets 2 arguments : <fp> and <8192>

Member functions implicitely get their object as first argument, this
is why you get this error. So you have 2 possibilities : either read()
doesn't take an argument anymore, or read() is not a member of fp.

Anthony B.

On 8/18/05, Andrey Smirnov <Andrey.Smirnov at sun.com> wrote:
> I am getting the following traceback after upgrading my app to Python
> 2.4.1.  It's telling me that there is an error in Parser.py.  It tells
> me that 'fp.read(8192)' is given 2 arguments, but it is clearly not
> true.  Does anybody know what's going on here?
> 
> Traceback (most recent call last):
>   File "/opt/etext/lib/python2.4/site-packages/etext/enqueue.py", line
> 252, in work
>     worker(e.linkval, info)
>   File "/opt/etext/bin/etreceive", line 30, in worker
>     result = decode.searchfile(f)
>   File "/opt/etext/lib/python2.4/site-packages/etext/decode.py", line
> 43, in searchfile
>     return Email(f)
>   File "/opt/etext/lib/python2.4/site-packages/etext/decode.py", line
> 510, in __init__
>     self.child.append(Email(mf))
>   File "/opt/etext/lib/python2.4/site-packages/etext/decode.py", line
> 404, in __init__
>     msg = Parser().parse(f)
>   File "/opt/etext/lib/python2.4/email/Parser.py", line 65, in parse
>     data = fp.read(8192)
> TypeError: read() takes exactly 1 argument (2 given)
> 
> Thanks,
> Andre.
> 
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