how to separate hexadecimal

[jrlen balane]

On Wed, 02 Feb 2005 17:36:04 +1000, Nick Coghlan <ncoghlan at iinet.net.au> wrote:
> jrlen balane wrote:
> > i have a 4 digit hex number (2 bytes) and i want to separate it into 2
> > digit hex (1 byte each) meaning i want to get the upper byte and the
> > lower byte since i am going to add this two.
> > how am i going to do this?
> > should i treat it just like a normal string?
> > please help, thanks.
> >
> > ex. hexa = '0x87BE"  # what i want to do is:
> >       a = 0x87, b = 0xBE    # so that i could do this:
> >       c = a + b            #which should be equal to 0x145
> 
> divmod does what you want:
> 
> Py> val = 0x87be
> Py> hi, lo = divmod(val, 0x100)
> Py> hex(hi), hex(lo)
> ('0x87', '0xbe')
> Py> hex(hi + lo)
> '0x145'
> 
> Cheers,
> Nick.
> 
> --
> Nick Coghlan   |   ncoghlan at email.com   |   Brisbane, Australia
> ---------------------------------------------------------------
>              http://boredomandlaziness.skystorm.net
> --
> http://mail.python.org/mailman/listinfo/python-list
> 
would i be able to perform bitwise operation with the result?
say, i want to get the two's complement of the result, is this correct:

twos_complement = (~ hex(hi + lo)) + 1