convert list of tuples into several lists
Oliver Eichler
oliver.eichler at dspsolutions.de
Thu Feb 10 04:35:03 EST 2005
Pierre Barbier de Reuille wrote:
>
> Best answer is : try it :)
> use the "timeit" module (in the standard lib) to do so ...
Ok, (a second time. I hope the first post was cancelled as it was false)
import timeit
s = """\
a,b,c1,c2 = zip(*[(x[2],x[4], x[2]-x[1], x[2] - x[3]) for x in z])
"""
t = timeit.Timer(stmt=s,setup="z = [(1,2,3,4,5)]*1000")
print "%.2f usec/pass" % (1000000 * t.timeit(number=100000)/100000)
s ="""\
a = []
b = []
c1 = []
c2 = []
for x in z:
a.append(x[2])
b.append(x[4])
c1.append(x[2] - x[1])
c2.append(x[2] - x[3])
"""
t = timeit.Timer(stmt=s,setup="z = [(1,2,3,4,5)]*1000")
print "%.2f usec/pass" % (1000000 * t.timeit(number=100000)/100000)
for 100 elements:
oeichler at frog:~/tmp> python test.py
104.67 usec/pass
180.19 usec/pass
for 1000 elements:
oeichler at frog:~/tmp> python test.py
1432.06 usec/pass
1768.58 usec/pass
What do we learn? The zip-thingy is even faster than the for loop
Learned my lesson :)
Thanks to all
Oliver
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