a sequence question
duncan.booth at invalid.invalid
Fri Jan 28 10:30:43 EST 2005
Chris Wright wrote:
> 1) I want to iterate over a list "N at a time"
> sort of like:
> # Two at a time... won't work, obviously
> >>> for a, b in [1,2,3,4]:
> ... print a,b
l = [1, 2, 3, 4]
for a, b in zip(*[iter(l)]*2):
print a, b
zip(*[iter(seq)]*N) will group by N (but if there are any odd items at the
end it will ignore them).
map(None, *[iter(seq)]*N) will group by N padding the last item with None
if it needs to.
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