interpret 4 byte as 32-bit float (IEEE-754)
grante at visi.com
Sat Jan 15 13:08:54 EST 2005
On 2005-01-15, Scott David Daniels <Scott.Daniels at Acm.Org> wrote:
>> I've read some bytes from a file and just now I can't interpret 4 bytes
>> in this dates like a real value.
> OK, here's the skinny (I used blocks & views to get the answer):
> import struct
> bytes = ''.join(chr(int(txt, 16)) for txt in '3F 8C CC CD'.split())
> struct.unpack('>f', bytes)
Just be careful. That doesn't work for all 32-bit IEEE floating
>>> import struct
>>> bytes = '\xff\xff\xff\xff'
>>> print struct.unpack('>f',bytes)
0xffffff is _not_ -6.8...e38. It's a NaN.
IIRC, it doesn't work for infinities either. I haven't tried
Grant Edwards grante Yow! It's hard being
at an ARTIST!!
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