A replacement for lambda

Stefan Rank stefan.rank at ofai.at
Sat Jul 30 11:08:28 CEST 2005

on 30.07.2005 10:20 Paolino said the following:
> why (x**2 with(x))<(x**3 with(x)) is not taken in consideration?
> If 'with' must be there (and substitue 'lambda:') then at least the 
> syntax is clear.IMO Ruby syntax is also clear.

I am sorry if this has already been proposed (I am sure it has).

Why not substitue python-lambdas with degenerated generator expressions::

   (lambda x: func(x)) == (func(x) for x)

i.e. a one time callable generator expression (missing the `in` part). 
The arguments get passed into the generator, I am sure that can be 
combined with the PEP about passing args and Exceptions into a generator.

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