passing arguments to a function - do I need type ?
jgrahn-nntq at algonet.se
Sun Jul 10 14:35:08 CEST 2005
(You posted your question as a followup to oen of Xah Lee's musings.
That is not the best of ideas, since people with threaded newsreaders
tend not to see it. Just post (creating a new thread) next time.)
On Sun, 10 Jul 2005 11:19:31 +0100 (BST), Philipp H. Mohr <phm4 at kent.ac.uk> wrote:
> I got a newbie question, I have written the following distance function:
> def distance(self,element1, element2):
> dist = 0
> for n in range(len(element1)):
> dist = dist + pow((element1[n] - element2[n]),2)
> print 'dist' + dist
> return sqrt(dist)
> and in order to be able to use len() and index element1 the function
> needs to know that the arguments element1 and element2 are both listst or
> doesn't it ?
Yeah, or something else supporting len(x) and x[n].
> I get the following error msg:
> TypeError: len() of unsized object
> AND if I take len out I get:
> TypeError: unsubscriptable object
Well, that depends on the types of the arguments
you're passing to the method, doesn't it? A call like
works fine for me. And here is a slightly simpler implementation
which avoids len (thus accepting a wider range of argument types)
def distance(element1, element2):
for a, b in zip(element1, element2):
n = float(a-b)
dist += n*n
(Dunno if that's the correct formula for n-dimensional distance.
I have forgotten way too much math in the past ten years.)
// Jorgen Grahn <jgrahn@ Ph'nglui mglw'nafh Cthulhu
\X/ algonet.se> R'lyeh wgah'nagl fhtagn!
More information about the Python-list