Odd behaviour of regexp module

Martin clamhan at hotmail.com
Wed Jul 13 23:39:32 CEST 2005

Hi David,
              b.group() is equivalent to b.group(0), the entire RE
match. (^(.*?)\.) will give you 'dfsf.' for that input string.

What you want is b.group(1), the subgroup you're looking for  inside
the main RE. (.*?) which gives you 'dfsf', which is what you're
looking for.


On 13 Jul 2005 14:05:37 -0700, "David Veerasingam"
<vdavidster at gmail.com> wrote:

>It seems the grouping feature isn't behaving correctly.
>In [1]: a = 'dfsf.oct.ocfe'
>In [2]: b = re.match(r'^(.*?)\.', a); b.group()
>The expected result is 'dfsf'. Why did the regexp grab that period at
>the end?

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