A replacement for lambda

Paolino paolo_veronelli at tiscali.it
Sat Jul 30 10:20:36 CEST 2005

why (x**2 with(x))<(x**3 with(x)) is not taken in consideration?

If 'with' must be there (and substitue 'lambda:') then at least the 
syntax is clear.IMO Ruby syntax is also clear.


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