how to get name of function from within function?

Steven Bethard steven.bethard at gmail.com
Mon Jun 6 19:51:07 CEST 2005


Christopher J. Bottaro wrote:
> Steven Bethard wrote:
>>...     def _impl_wrapper(self, func):
>>...         def wrapper(*args, **kwargs):
>>...             try:
>>...                 return func(*args, **kwargs)
>>...             except:
>>...                 print "entered except"
>>...                 raise
>>...         return wrapper
>>...
[snip]
> 
> The problem is:
> 
>>>>c.func_b.__name__
> 
> 'wrapper'
> 
> That messes up SOAPpy's RegisterFunction() method which apparently depends
> on the __name__ of the function to publish it as an available SOAP
> function.

Hmm... Nasty.  If you were using Python 2.4, you could simply write it as:

     def _impl_wrapper(self, func):
         def wrapper(*args, **kwargs):
             try:
                 return func(*args, **kwargs)
             except:
                 print "entered except"
                 raise
         wrapper.__name__ = func.__name__
         return wrapper

Where you fix up the wrapper's __name__ attribute.  But I believe the 
__name__ attribute is read-only in Python 2.3...

STeVe



More information about the Python-list mailing list