parameter name conflict. How to solve?
Pierre Barbier de Reuille
pierre.barbier at cirad.fr
Tue Mar 8 14:38:30 CET 2005
Bo Peng a écrit :
> Dear list,
> If you ask: why do you choose these names? The answer is: they need to
> be conformable with other functions, parameter names.
> I have a function that pretty much like:
> def output(output=''):
> print output
> and now in another function, I need to call output function, with again
> keyword parameter output
> def func(output=''):
> Naturally, I get 'str' object is not callable. Is there a way to tell
> func that the first output is actually a function? (like in C++,
> ::output(output) )
What I'd suggest is :
that way, the function resolution is still dynamic, but you explicitly
ask for a name global and not local ...
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