Faster way to do this...

[Steve Holden]

Harlin Seritt wrote:
> I've got the following code:
> 
> nums = range(0)
> for a in range(100):
>    nums.append(a)
> 
> Is there a better way to have num initialized to a list of 100
> consecutive int values?
> 
Why not the simplest solution?

   a = range(100)

regards
  Steve