Python RegExp
D H
no at spam
Tue Mar 22 19:12:34 EST 2005
davidchipping at gmail.com wrote:
> I have a string which I wish to match using RE, however when I run my
> comparison (using the match method) on my machine it never returns,
> using the CPU fully.
In your case it may be simpler to just split the string into groups.
You don't even need regular expressions or a parser.
buff = r"#1 1 550 111 SYNC_PEER RES <YP>syncpeers=(id=54325432;add=10." \
"0.0.1;port=89;up=89),(id=97899;add=10.0.0.1;port=543;up=543)," \
"(id=54325432;add=10.0.0.1;port=89;up=8)"
tran, sess, ndto, ndf, cmd, dirr, rest = buff.split()
eq = rest.find("=")
parmname = rest[0:eq]
parms = rest[eq+1:].split(",")
for parm in parms:
parmitems = parm[1:-1].split(";")
for item in parmitems:
name, val = item.split("=")
print name, val
print "---"
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