Python List Issue
Fearnot003 at mchsi.com
Mon Mar 28 06:41:57 CEST 2005
Thanks, thats a really handy function
"Ron_Adam" <radam2 at tampabay.rr.com> wrote in message
news:mt1e41tuhn9fbn21842j2rctgr8sdlsds9 at 4ax.com...
> On Sun, 27 Mar 2005 09:01:20 GMT, "Nick L" <Fearnot003 at mchsi.com>
> >I've hit a brick wall on something that I'm guessing is pretty simple but
> >it's driving me nuts.
> Yes, I've ran across that too a few times.
> > How on earth can I make a complete seperate copy of a list with out
> >being a attached to the original in any way shape or form so that I can
> >modifiy if at will and not worry about the original?
> This routine copies a list of lists.
> # Makes a copy of a list of lists
> # Containing simple data.
> def copylistlist(alist):
> if type(alist) is list:
> copy = 
> for i in alist:
> if type(i) is list:
> i = copylistlist(i)
> return copy
> bob = [[[0, 0]]]
> final = copylistlist(bob)
> print 'bob:'bob
> print 'Final:'final
> This still doesn't create new items within the new list. but with
> literal data consisting of letters and numbers, it will work.
> If you are working with a data tree, you may be able to modify this to
> do what you want. Just add a test in the inner loop for the data you
> want to modify.
> >Any ideas, suggestions, comments are greatly appreciated
> Hope that helps.
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