parameter name conflict. How to solve?

[Bo Peng]

Dear list,

If you ask: why do you choose these names? The answer is: they need to 
be conformable with other functions, parameter names.

I have a function that pretty much like:

def output(output=''):
   print output

and now in another function, I need to call output function, with again 
keyword parameter output

def func(output=''):
   output(output=output)

Naturally, I get 'str' object is not callable. Is there a way to tell 
func that the first output is actually a function? (like in C++, 
::output(output) )

Thanks.
Bo