any Python equivalent of Math::Polynomial::Solve?
Alex Renelt
renelt at web.de
Thu Mar 3 14:21:20 EST 2005
Cousin Stanley wrote:
> Alex ....
>
> Thanks for posting your generalized numarray
> eigenvalue solution ....
>
> It's been almost 30 years since I've looked at
> any characteristic equation, eigenvalue, eignevector
> type of processing and at this point I don't recall
> many of the particulars ....
>
> Not being sure about the nature of the monic( p ) function,
> I implemented it as an element-wise division of each
> of the coefficients ....
This is correct. The aim is that p has a leading coefficient that equals 1.
>
> Is this anywhere near the correct interpretation
> for monic( p ) ?
>
> Using the version below, Python complained
> about the line ....
>
> . M[ -1 , : ] = -p[ : -1 ]
>
Works for me. Did you perhaps use a list (type(p) == type([])) for p?
Then python does not know what -p means (numeric or numarray does).
> So, in view of you comments about slicing in you follow-up,
> I tried without the slicing on the right ....
>
> . . M[ -1 , : ] = -p[ -1 ]
>
That's wrong because you don't set a slice but a single item!
Old code should work. We need all coefficients but the leading coeff. So
take the slice p[:-1].
> The following code will run and produce results,
> but I'm wondering if I've totally screwed it up
> since the results I obtain are different from
> those obtained from the specific 5th order Numeric
> solution previously posted here ....
>
>
> . from numarray import *
> .
> . import numarray.linear_algebra as LA
> .
> . def monic( this_list ) :
> .
> . m = [ ]
> .
> . last_item = this_list[ -1 ]
> .
> . for this_item in this_list :
> .
> . m.append( this_item / last_item )
> .
> . return m
your function equals the following one:
def monic(p): return p / p[-1]
But you have to ensure that p is an array object. It does element-wise
operations per default.
Remember we need future division or take float(p[-1]) or the denominator.
> .
> .
> . def roots( p ) :
> .
> . p = monic( p )
> .
> . n = len( p ) # degree of polynomial
The degree is len(p) -1 or something smaller (some people are calling
len(p) -1 a "degree bound" instead). It is smaller if p contains leading
zeros which should be deleted, e.g. P(x) = x^2 + 4 x + 4 could be entered as
p = array([4, 4, 1, 0, 0])
which would produce a deg of 4 instead of 2.
> .
> . z = zeros( ( n , n ) )
> .
> . M = asarray( z , typecode = 'f8' ) # typecode = c16, complex
> .
> . M[ : -1 , 1 : ] = identity( n - 1 )
> .
> . M[ -1 , : ] = -p[ -1 ] # removed : slicing on the right
> .
> . return LA.eigenvalues( M )
> .
> .
> . coeff = [ 1. , 3. , 5. , 7. , 9. ]
remember to use an array or convert it on-the-fly inside your roots
function:
M[-1,:] = - asarray(p)[:-1]
> .
> . print ' Coefficients ..'
> . print
> . print ' %s' % coeff
> . print
> . print ' Eigen Values .. '
> . print
> .
> . eigen_values = roots( coeff )
> .
> . for this_value in eigen_values :
> .
> . print ' %s' % this_value
> .
>
> Any clues would be greatly appreciated ....
>
>
Hope that helps.
Alex
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