String Splitter Brain Teaser

Doug Schwarz see at
Mon Mar 28 21:19:02 CEST 2005

In article <mailman.925.1111963149.1799.python-list at>,
 James Stroud <jstroud at> wrote:

> Hello,
> I have strings represented as a combination of an alphabet (AGCT) and a an 
> operator "/", that signifies degeneracy. I want to split these strings into 
> lists of lists, where the degeneracies are members of the same list and 
> non-degenerates are members of single item lists. An example will clarify 
> this:
> gets split to
> [['A'], ['T'], ['T', 'G'], ['A'], ['T'], ['A', 'G']]

How about this?

import re
s = "ATT/GATA/G"
result1 = re.findall(r"./.|.", s)
consensus = [c.split("/") for c in result1]

Doug Schwarz
Make obvious changes to get real email address.

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