how to start a process and get it's pid?

[Daniel Crespo]

> >>> import subprocess
> >>> p = subprocess.Popen("c:/windows/notepad.exe")
> >>> p.pid

> 1948

Yes, it works. But in my case, I need to run the program totally
separated from my main program. So, when I start a new program through
subprocess, it doesn't unlink. I mean, if I close my main app, so does
the launched program. With startfile() it does the job, but I then I
have to find what pid is through win32all module, etc.

it would be very good if I can use spawnl

Daniel