the name of a module in which an instance is created?
steven.bethard at gmail.com
Tue Nov 22 20:19:15 CET 2005
> I'm not sure I got your problem correctly, however see if this helps:
> $ cat > test.py
> class myclass:
> name = __module__
> >>> import test
> >>> a = test.myclass()
> >>> a.name
> This works, as we define "name" to be a class attribute.
> Is this useful to you?
Unfortunately, no, this is basically what I currently have. Instead of
a.name printing 'test', it should print '__main__'. I want the name of
the module in which the *instance* is created, not the name of the
module in which the *class* is created.
P.S. Note that I already discussed two possible solutions which I didn't
much like: (1) pass __name__ to the class instance, e.g. ``a =
test.myclass(__name__)`` or (2) declare an empty sublcass of myclass in
the second module (in your case, at the interactive prompt).
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