directory listing

[Michael Konrad]

"Fredrik Lundh" <fredrik at pythonware.com> wrote:
 
> "SU News Server" <mkonrad at syr.edu> wrote:
> 
>> I've struggled with this for quite a while and I'm am just not sure
>> what is going on. I have the following code
>> import os
>>
>> def buildList( directory='/Users/mkonrad' )
>>
>> dirs = [ ]
>>
>> listing = os.listdir(directory)
>>
>> for x in listing:
>>       if os.path.isdir(x):
>>            dirs.append(x)
>>
>> return dirs
>>
>> This always returns an empty list.
>> Now if I change it so that directory='.' or directory=os.getcwd()
>> Then it returns a list of directories.
> 
> hint: if you're not sure what's going on in your program, adding
> a print statement or two is an easy way to figure it out.  like, say:
> 
>     for x in listing:
>         print x
>         if os.path.isdir(x):
>             dirs.append(x)
> 

Did that and I was just getting a bunch of [ ].

> (try this before you continue)
> 
>    :
>    :
>    :
> 
> the problem is that os.listdir returns a list of filenames, without
> the preceeding directory name.  you can add an os.path.join
> 
>     for x in listing:
>         x = os.path.join(directory, x)
>         if os.path.isdir(x):
>             dirs.append(x)

OK. This works except each entry in dirs now includes the full path. 
Is there an unjoin? :) I haven't spent any time trying to work this out.

> 
> or use the glob module instead:
> 
>     listing = glob.glob(os.path.join(directory, "*"))
> 
> hope this helps!
> 
> </F>
> 
> 
> 
>