func(*params)

[Fredrik Lundh]

David Duerrenmatt wrote:

> For some reasons, I've to use Python 1.5.2 and am looking for a workaround:
>
> In newer Python versions, I can call a function this way:
>
> func = some_function
> func(*params)
>
> Then, the list/tuple named params will automatically be "expanded" and
> n=len(params) arguments will be submitted.
>
> Python 1.5.2 doesn't support this kind of function call.

use

    apply(func, params)

or

    result = apply(func, params)

more info:

    >>> help(apply)
    Help on built-in function apply in module __builtin__:

    apply(...)
        apply(object[, args[, kwargs]]) -> value

        Call a callable object with positional arguments taken from the tuple args,
        and keyword arguments taken from the optional dictionary kwargs.
        Note that classes are callable, as are instances with a __call__() method.

        Deprecated since release 2.3. Instead, use the extended call syntax:
            function(*args, **keywords).

</F>