write a loopin one line; process file paths

Xah Lee xah at xahlee.org
Tue Oct 18 23:56:32 CEST 2005


is there a way to condense the following loop into one line?

# -*- coding: utf-8 -*-
# python

import re, os.path

imgPaths=[u'/Users/t/web/Periodic_dosage_dir/lanci/t4/oh/DSCN2059m-s.jpg',
u'/Users/t/web/Periodic_dosage_dir/lanci/t4/oh/DSCN2062m-s.jpg',
u'/Users/t/web/Periodic_dosage_dir/lanci/t4/oh/DSCN2097m-s.jpg',
u'/Users/t/web/Periodic_dosage_dir/lanci/t4/oh/DSCN2099m-s.jpg',
u'/Users/t/web/Icons_dir/icon_sum.gif']

# change the image path to the full sized image, if it exists
# that is, if image ends in -s.jpg, find one without the '-s'.
temp=imgPaths[:]
imgPaths=[]
for myPath in temp:
    p=myPath
    (dirName, fileName) = os.path.split(myPath)
    (fileBaseName, fileExtension)=os.path.splitext(fileName)
    if(re.search(r'-s$',fileBaseName,re.U)):
        p2=os.path.join(dirName,fileBaseName[0:-2]) + fileExtension
        if os.path.exists(p2): p=p2
    imgPaths.append(p)

temp=[]
print imgPaths

 Xah
 xah at xahlee.orghttp://xahlee.org/




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