yet another noob question

[Stargaming]

Jason Nordwick schrieb:
> Or without filter:
> 
> from operator import add
> def pr(x): print x
> def cross(x,y): return reduce(add, [[a+b for b in y] for a in x])
> x=map(pr, reduce(cross, [map(str,range(1,6))]*5))
> 
[...]

reduce(add, list) is the same as sum(list) and is only half as fast as sum:
 >>> from timeit import Timer
 >>> sum(Timer("sum(range(500))").repeat(200, 1000))/200
0.055693786500798058
 >>> sum(Timer("reduce(add, range(500))", "from operator import 
add").repeat(200, 1000))/200
0.10820861031220445
 >>>

Also note that reduce will be removed in Python 3000.