Datetime objects

[Lad]

John Machin wrote:
> Lad wrote:
> > Sybren Stuvel wrote:
> > > Lad enlightened us with:
> > > > How can I find days and minutes difference between two datetime
> > > > objects?
> > > > For example If I  have
> > > > b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
> > > > a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)
> > >
> > > diff = b - a
> >
> > Ok, I tried
> >
> > >>> diff=b-a
> > >>> diff
> > datetime.timedelta(0, 52662, 922000)
> > >>> diff.min
> > datetime.timedelta(-999999999)
>
> Reread the manual:
>
> 1. "min" is minIMUM, not minUTES
>
> 2. You need:
> >>> diff.days
> 0
> >>> diff.seconds
> 52662
> >>> diff.microseconds
> 922000
> >>> minutes = (diff.seconds + diff.microseconds / 1000000.0) / 60.0
> >>> minutes
> 877.71536666666668
> >>>
> >
> >
> > which is not good for me.
> >
> > So I tried to use toordinal like this
> > diff=b.toordinal()-a.toordinal()
> >
> > but I get
> > diff=1
> >
> > Why?
>
> because toordinal() works only on the date part, ignoring the time
> part.
> 
> HTH,
> John
Thank you for the explanation