how do you get the name of a dictionary?

[Georg Brandl]

Andy Terrel wrote:
> Why bang your head?

Because there's no chance that the original request is sane.

If you want your objects to know their name, give them a name as an attribute.

>  It was a stupid hack that has lots of problems,
> but done in a way that is readable.  Sure I could do something more
> functional or one lined like:
> 
> Banana={}
> names = filter(lambda x:id(eval(x))==id(Banana),dir())
> 
> but I am guessing that it is harder to read by many.  Anywho I can
> think of plenty of reasons it would fail, but it really depends on the
> app.

Georg