UnboundMethodType and MethodType

[Kirk McDonald]

Schüle Daniel wrote:
> Hello all,
> 
>  >>> class Q:
> ...     def bar(self):
> ...             pass
> ...
>  >>> import types
>  >>> types.UnboundMethodType is types.MethodType
> True
>  >>>
>  >>> type(Q.bar)
> <type 'instancemethod'>
>  >>>
>  >>> q = Q()
>  >>> type(q.bar)
> <type 'instancemethod'>
>  >>>
>  >>> type(q.bar) is types.UnboundMethodType
> True
>  >>> q.bar
> <bound method Q.bar of <__main__.Q instance at 0x4042756c>>
>  >>>
> 
> I think is not very consistent
> notice q.bar is bounded although type(q.bar)
> says it's types.UnboundedMethodType
> what do you think?
> 
> Regard, Daniel
> 

I think it's perfectly consistent:

 >>> class B(object):
...     def bar(self): pass
...
 >>> B.bar
<unbound method B.bar>
 >>> type(B.bar)
<type 'instancemethod'>
 >>> b = B()
 >>> b.bar
<bound method B.bar of <__main__.B object at 0xb7bd544c>>
 >>> type(b.bar)
<type 'instancemethod'>
 >>> id(B.bar)
-1211888788
 >>> id(b.bar)
-1211888788

It's the same function, whether it's bound or not. Thus, it should 
always have the same type. It's simply called in different ways. You can 
just as easily say:

 >>> B.bar(b)

As:

 >>> b.bar()

-Kirk McDonald