calculating on matrix indices
Travis E. Oliphant
oliphant.travis at ieee.org
Thu Feb 16 20:54:27 EST 2006
Brian Blais wrote:
> Hello,
>
> In my attempt to learn python, migrating from matlab, I have the following problem.
> Here is what I want to do, (with the wrong syntax):
>
> from numpy import *
>
> t=arange(0,20,.1)
> x=zeros(len(t),'f')
>
> idx=(t>5)
> tau=5
> x[idx]=exp(-t[idx]/tau) # <---this line is wrong (gives a TypeError)
Hi Brian,
Just to let you know, you are more likely to get good answers by mailing
numpy-discussions at lists.sourceforge.net then posting to this list.
The indexing technique you are using is actually fine. The trouble you
are having is that t is a double-precision array (and thus so is
exp(-t[idx]/tau) while x is a single-precision array.
Compare:
x.dtype.name
t.dtype.name
Because you are trying to store something with greater precision into an
array with less precision you get a TypeError.
So, either change x to be double precision:
x = zeros(len(t), float)
#the default Python float is doubleprecision
or change t to be single precision:
t = arange(0,20,.1,dtype=single)
Good luck,
-Travis
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