regular expresson for Unix and Dos Lineendings wanted

[Franz Steinhaeusler]

On Thu, 23 Feb 2006 17:41:47 +0000, Martin Franklin
<mfranklin1 at gatwick.westerngeco.slb.com> wrote:

>Franz Steinhaeusler wrote:
>> On Thu, 23 Feb 2006 13:54:50 +0000, Martin Franklin
>> <mfranklin1 at gatwick.westerngeco.slb.com> wrote:
>> 
>>>>>>> r="erewr    \r\nafjdskl     "
>>>> 'erewr    \r\nafjdskl'
>>>>
>>>> 2) Unix
>>>>>>> r="erewr    \nafjdskl     "
>>>> 'erewr\nafjdskl'
>>> why not use string methods strip, rstrip and lstrip
>>>
>> 
>> because this removes only the last spaces,
>>>>> r
>> 'erewr    \r\nafjdskl     '
>>>>> r.rstrip()
>> 'erewr    \r\nafjdskl'
>> 
>> I want:
>> 'erewr\r\nafjdskl'
>> 
>> or for unix line endings
>> 'erewr\nafjdskl'
>> 
>
>
>how about one of these variations
>
>print 'erewr    \r\nafjdskl     '.replace(" ", "")
>print 'erewr    \r\nafjdskl     '.strip(" \t")
>
>

Version 1:

>>> w='erewr    \r\nafjdskl     '.replace(" ", "")
>>> w
'erewr\r\nafjdskl'
>>> w='erewr    \nafjdskl     '.replace(" ", "")
>>> w
'erewr\nafjdskl'
>>> w='word1 word2   \nafjdskl     '.replace(" ", "")
>>> w
'word1word2\nafjdskl'
>>> 

it replaces all spaces, not only the trailing whitespaces.


version 2:

>>> w = 'erewr    \r\nafjdskl     '.strip(" \t")
>>> w
'erewr    \r\nafjdskl'
>>> w = 'erewr    \nafjdskl     '.strip(" \t")
>>> w
'erewr    \nafjdskl'
>>> w = 'word1 word2    \nafjdskl     '.strip(" \t")
>>> w
'word1 word2    \nafjdskl'
>>> 

I found a solution (not the most beautiful, but for 
my purpose sufficiently good.)
Given: a file has no mixed lineendings, so it is either
a dos or unix file (mac line endings not respected).


swin="erewr \r\nafjdskl "
sunix="erewr \nafjdskl "

Dos Line endings (at least on '\r' included)?
r is contents of a file:

helpchar = ''
if r.find('\r') != -1:
    helpchar = '\r'
retrailingwhitespacelf = re.compile('(?<=\S)[ \t'+helpchar+']+$',
re.MULTILINE)
newtext, n = retrailingwhitespace.subn(helpchar, r)
if n > 1:
   r = newtext


-- 
Franz Steinhaeusler