How to generate (enumerate) 2**N tuples representing all vertices of unit hypercube in N-dimensional hyperspace ?

[Claudio Grondi]

Heiko Wundram wrote:
> Paul Rubin wrote:
> 
>>def perm(n):
>>   return [tuple([(1,-1)[(t>>i)%2] for i in xrange(n)])
>>              for t in xrange(2L**n)]
> 
> 
> or replace that with:
> 
> def perm(n):
>    return (tuple(((1,-1)[(t>>i)%2] for i in xrange(n)))
>            for t in xrange(2L**n))
> 
> to get a generator like in Paul's first example. Only works with Python 2.4+
> though.
> 
> --- Heiko.

Isn't this kind of coding beeing the result of suffering from the 
post-pyContest illness syndrom?

Or is there another reason behind writing it that way sacrificing 
readability like usage of less CPU time to run the code?

Or am I alone having trouble to read this kind of code because not 
experienced enough in writing Python scripts?

Claudio