how to scrape url out of href

homepricemaps at homepricemaps at
Mon Jan 2 05:02:16 CET 2006

mike's code worked like a charm.  i have one more question.  i have an
href which looks like this:

<td class="all">
    <a class="btn" name="D1" href="">

i thought i would use this code to get the href out but it fails, gives
me a keyerror:

for incident in row('td', {'class':'all'}):
		n = incident.findNextSibling('a', {'class': 'btn'})
		link = incident.findNextSibling['href'] + "','"

any idea what i'm doing wrong here with the syntax?  thanks in advance

More information about the Python-list mailing list