steve at REMOVETHIScyber.com.au
Mon Jan 23 16:33:18 EST 2006
On Mon, 23 Jan 2006 17:41:55 +0000, Mathijs wrote:
> Op 19 jan 2006 vond "markscala at gmail.com" :
>> another approach:
>> ref = [2,2,4,1,1]
>> lis = [2,2,5,2,4]
>> len([ref.pop(ref.index(x)) for x in lis if x in ref])
> This is the type of solution I was hoping to see: one-liners, with no use
> of local variables.
Because you like unreadable, incomprehensible, unmaintainable code?
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