Attaching functions to objects as methods

[John Machin]

On 8/07/2006 11:01 AM, tac-tics wrote:
> Experimenting, I found that
> 
>>>> x.fun = lambda: fun(x)
> 
> works as well. Any comments on this way?
> 

Appears to work. Less typing for a no-argument method,  but you need to 
specify the argument list *twice* compared with *zero* times with the 
types.MethodType way of doing it.

 >>> x=K()
 >>> x.metho = lambda(a): own(x, a)
 >>> x.metho('abcde')
own
 >>> x.ozz
'abcde'
 >>>