split a line, respecting double quotes

[faulkner]

sorry, i didn't read all your post.
def test(s):
    res = ['']
    in_dbl = False
    escaped = False
    for c in s:
        if in_dbl:
            if escaped:
                res[-1] += c
                if c != '\\':
                    escaped = False
            else:
                res[-1] += c
                if c == '\\':
                    escaped = True
                elif c == '"':
                    res.append('')
                    in_dbl = False
        elif c == ' ':
            res.append('')
        elif c == '"':
            res.append('')
            res[-1] += c
            in_dbl = True
        else:
            res[-1] += c
    while '' in res:
        res.remove('')
    return res

faulkner wrote:
> import re
> re.findall('\".*\"|\S+', raw_input())
>
> Jim wrote:
> > Is there some easy way to split a line, keeping together double-quoted
> > strings?
> >
> > I'm thinking of
> >   'a b c "d e"'  --> ['a','b','c','d e']
> > .  I'd also like
> >   'a b c "d \" e"'  --> ['a','b','c','d " e']
> > which omits any s.split('"')-based construct that I could come up with.
> > 
> > Thank you,
> > JIm