Calling every method of an object from __init__
python.list at tim.thechases.com
Mon Jun 19 22:22:10 CEST 2006
> Is there a simple way to call every method of an object from its
> For example, given the following class, what would I replace the
> comment line in __init__() with to result in both methods being called?
> I understand that I could just call each method by name but I'm looking
> for a mechanism to avoid this.
> class Foo(object):
> def __init__(self):
> #call all methods here
> def test(self):
> print 'The test method'
> def hello(self):
> print 'Hello user'
>>> class Foo(object):
... def __init__(self):
... for method in dir(self):
... if method == method.strip("_"):
... f = getattr(self, method)
... if callable(f): f()
... def test(self):
... print "in test..."
... def hello(self):
... print "in hello..."
>>> x = Foo()
This does assume that the method's signature takes no parameters
and that you don't want to try and call "special" methods such as
__add__ or "private" methods (usually indicated by leading
underscores too) while you're going through the available methods.
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