returning index of minimum in a list of lists

jwelby julius.welby at gmail.com
Wed Jun 21 18:43:00 CEST 2006


def minIndexFinder(seq):
	mins = []
	listIndex = 0
	result = []
	for item in seq:
		mins.append([listIndex,min(item),item.index(min(item))])
		listIndex += 1
	lowest = min([x[1] for x in mins])
	for item in mins:
		if item[1] == lowest:
			result.append([item[0], item[2]])
	return result

A bit more verbose, but maybe slightly more readable??

I probably should have used enumerate like Paul did.

For the index of the *first* (or only) occurence of the minimum value
in a list of numbers you can just use:

seq.index(min(seq))




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