Separating elements from a list according to preceding element
mahs at telcopartners.com
Mon Mar 6 00:48:04 CET 2006
Rob Cowie wrote:
> I'm having a bit of trouble with this so any help would be gratefully
> After splitting up a url I have a string of the form
> 'tag1+tag2+tag3-tag4', or '-tag1-tag2' etc. The first tag will only be
> preceeded by an operator if it is a '-', if it is preceded by nothing,
> '+' is to be assumed.
> Using re.split, I can generate a list that looks thus:
> ['tag1', '+', 'tag2', '+', 'tag3', '-', 'tag4']
> I wish to derive two lists - each containing either tags to be
> included, or tags to be excluded. My idea was to take an element,
> examine what element precedes it and accordingly, insert it into the
> relevant list. However, I have not been successful.
> Is there a better way that I have not considered? If this method is
> suitable, how might I implement it?
> Thanks all,
> Rob Cowie
Since you're already using a regexp, why not modify it to group the operators
with their tags? :
>>> import re
>>> source = "tag1+tag2+tag3-tag4"
>>> tagfinder = re.compile("([+-]?)(\w+)")
>>> include = 
>>> exclude = 
>>> for op, tag in tagfinder.findall(source):
... if op == "-":
['tag1', 'tag2', 'tag3']
(Example assumes that a tag can be matched by \w+ and that there
is no space between the operators and their tags)
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