assignment in a for loop

Ben Finney bignose+hates-spam at benfinney.id.au
Wed May 17 07:11:51 CEST 2006


"MackS" <mackstevenson at hotmail.com> writes:

[MackS, please don't top-post.]

> Suppose I want to do modify all arguments which are passed to a
> function. Do I need to use a list comprehension such as
> 
> def f(arg1,arg2,arg3):
> 
>      arg1,arg2,arg3 = [i+1 for i in (arg1,arg2,arg3)]
>      ...
> 
> This would be awful when, eg, one adds an argument to the function
> definition. It would require edition of the code at two different
> locations.

If you anticipate increasing the number of values passed to the
function, and you're doing the same operation on all of them, why not
pass in a list::

    >>> def add_one_to_each(nums):
    ...     """ Makes a new list with each value incremented by one. """
    ...
    ...     incremented_nums = [x+1 for x in nums]
    ...     return incremented_nums
    ...
    >>> foo = [3, 5, 8]
    >>> bar = add_one_to_each(foo)
    >>> bar
    [4, 6, 9]

-- 
 \     "Some mornings, it's just not worth chewing through the leather |
  `\                                          straps."  -- Emo Philips |
_o__)                                                                  |
Ben Finney




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