Replace

[Larry Bates]

Eric wrote:
> I have a string...
> 
> str = "tyrtrbd =ffgtyuf == =tyryr =u=p ttttff"
> 
> I want to replace the characters after each '=', what I ended up doing is
> somthing like this...
> 
> buf = list(str)
> newchr = '#'
> 
> count = 0
> for i in range(len(buf)):
>   if buf[count] == '=':
>     buf[count + 1] = newchr
>     count = count + 1
>   else:
>     count = count + 1
> 
> newstr = ''.join(buf)
> 
> Is there a better, faster way of doing it? Using somthing like
> str.index() dosn't work because...
> 
> str = "hello world"
> for i in str:
>   print str.index(i)
>  
> 0
> 1
> 2
> 2
> 4
> 5
> 6
> 4
> 8
> 2
> 10
> 
> Every 'e' in "hello world" has the same index value. Am i missing somthing?

Split the string on '=', and join it back with '=#'.

s='=#'.join(s.split('='))

-Larry Bates