CSV module, DictReader problem (bug?)
Fredrik Lundh
fredrik at pythonware.com
Wed Nov 1 15:47:18 EST 2006
Jeff Blaine wrote:
> It's been a year or so since I written Python code, so maybe
> I am just doing something really dumb, but...
>
> Documentation
> =============
>
> class DictReader(csvfile[,fieldnames=None,
> [,restkey=None[, restval=None[, dialect='excel'
> [, *args, **kwds]]]]])
>
>
> Create an object which operates like a regular reader
> but maps the information read into a dict whose keys
> are given by the optional fieldnames parameter. If the
> fieldnames parameter is omitted, the values in the
> first row of the csvfile will be used as the fieldnames.
>
> Code
> ====
>
> import csv
>
> r = csv.DictReader('C:\Temp\Book1.csv')
> print r.next()
> # EOF
here's the documentation for the regular reader, from Python 2.5:
reader(...)
csv_reader = reader(iterable [, dialect='excel']
[optional keyword args])
for row in csv_reader:
process(row)
The "iterable" argument can be any object that returns a line
of input for each iteration, such as a file object or a list.
...
so the reader is simply looping over the characters in your filename. try
r = csv.DictReader(open('C:\Temp\Book1.csv'))
instead.
</F>
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