remove a list from a list

John Henry john106henry at
Fri Nov 17 21:01:01 CET 2006

The curve ball is the case insensitivity otherwise it's a
straightforward set operation.

I wonder if it's possible to sub-class set and make the item
comparision case insensitive.

Anybody knows how to do that?

Tim Chase wrote:
> > Yeah, I ended up doing a similar kind of loop. That is pretty messy.
> >
> > Is there any other way?
> I've already provided 2 (or 3 depending on how one counts)
> solutions, each of which solve an interpretation of your original
> problem, neither of which involve more than 3 lines of fairly
> clean code.  Perhaps a little more context regarding what you
> *want* to do would help.  However, I suspect that answer is
> "there is no *cleaner* way to do it".
> Unless you're modifying an existing list that is referenced
> elsewhere, the reassignment (l = [x for x in l ...]) solution
> should work just fine.  Thus, unless you have a situation akin to:
> 	g = l
> 	l = [x for x in l if x.lower() not in s]
> 	assert(thing_from_s not in g)
> then just reassign "l".  If not, use the loop.  It's that easy
> and clean.  Don't try to opaquify it by collapsing it further.
> Perhaps, if your loop is messy, use my clean loop suggestion.
> -tkc

More information about the Python-list mailing list