remove a list from a list

[Tim Chase]

> Yeah, I ended up doing a similar kind of loop. That is pretty messy.
> 
> Is there any other way?

I've already provided 2 (or 3 depending on how one counts) 
solutions, each of which solve an interpretation of your original 
problem, neither of which involve more than 3 lines of fairly 
clean code.  Perhaps a little more context regarding what you 
*want* to do would help.  However, I suspect that answer is 
"there is no *cleaner* way to do it".

Unless you're modifying an existing list that is referenced 
elsewhere, the reassignment (l = [x for x in l ...]) solution 
should work just fine.  Thus, unless you have a situation akin to:

	g = l
	l = [x for x in l if x.lower() not in s]
	assert(thing_from_s not in g)

then just reassign "l".  If not, use the loop.  It's that easy 
and clean.  Don't try to opaquify it by collapsing it further. 
Perhaps, if your loop is messy, use my clean loop suggestion.

-tkc