Using SimpleXMLRPCServer in a Windows Service

[Gabriel Genellina]

At Thursday 23/11/2006 06:52, Rudy Schockaert wrote:

>After some Googling I found a post of someone who wanted to do exactly
>as what I want to do now.
>There is however a problem in his code that makes the service fails
>after the first connection. I slightly modified his code and now I can
>run the service longer before I run into trouble.
>I then tried making the SimpleXMLRPCServer multi-threaded, hoping the
>problem would disappear, but no avail.
>The code is as follows:
>The commented part in the while loop is from the original code.

The original (commented-out) code should be fine. You have to wait 
for 2 events: the service stop signal, or an incoming connection.
Anyway, you always have to catch exceptions; override handle_error at least.

Another approach (not involving events) would be to set a (not so 
big) timeout on the socket, and test for self.stop_requested on each iteration.

>         server = ThreadedSimpleXMLRPCServer(("", 8080))
>         object = OBJECT()
>         server.register_instance(object)
>         self.socket = server.socket
>
>         while 1:
>             #win32file.WSAEventSelect(server,
>self.hSockEvent,win32file.FD_ACCEPT)
>             #rc =
>win32event.WaitForMultipleObjects((self.hWaitStop,self.hSockEvent), 0,
>win32event.INFINITE)
>             #if rc == win32event.WAIT_OBJECT_0:
>             #    break
>             #else:
>             #    server.handle_request()
>             #    win32file.WSAEventSelect(server,self.hSockEvent, 0)
>             #    #server.serve_forever()  ## Works, but breaks the


-- 
Gabriel Genellina
Softlab SRL 

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