len(var) is [CONSTANT] equal to len(var) == [CONSTANT]?

[Tor Erik Soenvisen]

Steven D'Aprano <steve at REMOVE.THIS.cybersource.com.au> wrote in
news:pan.2006.11.23.11.27.54.956445 at REMOVE.THIS.cybersource.com.au: 

> On Thu, 23 Nov 2006 10:48:32 +0000, Tor Erik Soenvisen wrote:
> 
>> Hi,
>> 
>> 
>> (len(['']) is 1) == (len(['']) == 1) => True
> 
> You shouldn't rely on this behaviour:
> 
>>>> x = 100000
>>>> len('a' * x) == x
> True
>>>> len('a' * x) is x
> False
> 
> (Your results may vary -- this depends on the implementation.)
> 
> 
> 
>> Is this the case for all numbers? I've tried running the following:
>> 
>> for i in range(10000):
>>          for j in range(10000):
>>           if i != j:
>>                assert id(i) != id(j), 'i=%d, j=%d, id=%d' % (i, j, id
>> (i))
>> 
>> which executes fine. Hence, 0-9999 is okey... 
> 
> This doesn't necessarily hold for all integers -- again, it depends on
> the implementation, the precise version of Python, and other factors.
> Don't rely on "is" giving the same results as "==".
> 
>>>> (1+2+3+4+5)**7 == 15**7
> True
>>>> (1+2+3+4+5)**7 is 15**7
> False
> 
>> But this is a relatively 
>> small range, and sooner or later you probably get two numbers with
>> the same id... Thoughts anyone?
> 
> No, you will never get two objects existing at the same time with the
> same id. You will get two objects that exist at different times with
> the same id, since ids may be reused when the object is deleted.
> 
>> PS: For those of you who don't know: keyword is compares object
>> identities 
> 
> Exactly. There is no guarantee that any specific integer object "1"
> must be the same object as another integer object "1". It may be, but
> it isn't guaranteed.
> 
> I think the only object that is guaranteed to hold for is None. None
> is a singleton, so there is only ever one instance. Hence, you should
> test for None with "obj is None" rather than ==, because some custom
> classes may do silly things with __eq__:
> 
> class Blank(object):
>     """Compares equal to anything false, including None."""
>     def __eq__(self, other):
>         return not other
> 
> 
I've seen code like this:

if type([]) is list:
    	print 'Is list'

which seem to work. And also I've seen "var is None", as you mention.